MO→⎯⎯⎯bisects ∠LMN, m∠LMN=5x−23, m∠LMO=x+32. Find m∠NMO. The diagram is not to scale.a.61b.45.75c.91.5d.66. a . Here, MO  bisects ∠LMN.

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MO bisects angle LMO = 6x-22, and angle NMO = 2x + 34. solve for x and find angle LMN. - 711370

7, mo bisects angle lmn,m angle lmn = 6x-20, m angle lmo= x+32 find m angle nmo but how if i don't know what lmn is Jul 02 2015 01:18 PM. 1 Approved Answer. Cecilia answered on July 02, 2015. 3 Ratings, (9 Votes) mo bisects angle lmn,m angle lmn Q. Find the OTHER ENDPOINT of the segment with the endpoint of (-4, 5) and midpoint of (7, -9) h x?b?u"q?j%?j &m ($)*? m h -.z 0c, h -.z 0c, h chh gg0 h 8. In the figure (not drawn to scale), MO $$$→ bisects ∠LMN, m∠LMO=(13x −31)°, and m∠NMO=(x +53)°. Solve for x and find m∠LMN.

Mo bisects lmn 5x-23

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solve for x and find angle LMN. - 711370 Mo bisects Angles-> SOLUTION: MO bisects

0.5 ____ 21. Find the coordinates of the midpoint of the segment whose endpoints are H(8, 2) and K(6, 10).

1. Ray MO bisects ∠LMN, m∠LMO=8x−23, and m∠NMO=2x+37. Solve for x and find m∠LMN. The diagram is not to scale. A. x=9, m∠LMN=98 B. x=9, m∠LMN=49 *C. x=10, m∠LMN=114 D. x=10, m∠LMN=57 2. Ray MO bisects ∠LMN, m∠LMN=5x−23, m∠LMO=x+32. Find m∠NMO. The diagram is not to scale. *A. 61 B. 45.7 C. 91.5 D. 66 3.

I do not know how to solve this question and I have tried all that I know. Please help.. Math.

7. In the figure (not drawn to scale), MO bisects ∠LMN, m LMO x∠ = −17 32, and m NMO x∠ = +144. Solve for x and find m LMN∠ . L O M N [A] 7, 43 [B] 11, 310 [C] 7, 87 [D] 11, 219 8. Name the segment that has a length which represents the distance between C and AG. 9. What is the name of the segment that is the shortest path between O

Mo bisects lmn 5x-23

m∠XLM + m∠LMN MO. →. bisects ∠LMN, m∠LMO = 8x − 23, and m∠NMO = 2x + 37. Solve for x Find the value of the variable if m Ä l, m∠1=2x + 44 and m∠5=5x + 38.

Mo bisects lmn 5x-23

solve for x and find angle LMN. - 711370
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Mo bisects lmn 5x-23

10. If ∠R and ∠S are complementary and m∠R =35°, then 11. If ∠G and ∠H are supplementary and m 1.

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1 Answer to 1. MO bisects LMN, LMN = 5x-23, LMO = x+32. Find NMO. >>I got the answer 45.75 but I got it wrong. I do not know how to solve this question and I have tried all that I know.

Algebra -> Angles-> SOLUTION: Line MO bisects
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Ray MO bisects <LMN. Find x. 8x ­ 23 2x + 37 Sep 9­9:59 AM 1 Day_10_­_Test_Review_1­1_to_1­9 answers.notebook September 04, 

Soh•e the s-llnu11aneoU$ e CE= 5x − 1, determine each missing value. u ru bisects ∠PQR. ∠LMN?